35x^2+24x-9=0

Solution for 35x^2+24x-9=0 equation:

35x^2+24x-9=0

a = 35; b = 24; c = -9;
Δ = b2-4ac
Δ = 242-4·35·(-9)
Δ = 1836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1836}=\sqrt{36*51}=\sqrt{36}*\sqrt{51}=6\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-6\sqrt{51}}{2*35}=\frac{-24-6\sqrt{51}}{70}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+6\sqrt{51}}{2*35}=\frac{-24+6\sqrt{51}}{70}
$